Answer
Graph "B" is the correct sketching.
Work Step by Step
For $y = 3\sqrt{x},$
when $x=0, y=0$ and $x=1, y=3$
The curve passes through $(0,0)$ and $(1,3)$
Since the graph of $y=3\sqrt{x}$ is vertically stretched 3 times of the graph of $y=\sqrt{x}$, graph "B" is the correct sketching.
