Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Review Exercises - Page 41: 19

Answer

$p=q=7$

Work Step by Step

Similar triangles have corresponding sides in proportion. Side of length 16 corresponds to side of length 7 and side of length 16 corresponds to side of length p. This leads to the following proportion: $\frac{16}{7}=\frac{16}{p}$ Solving, $16\times7=16\times p$ $112=16p$ Dividing both sides by $16, $$p=7$. Side of length 16 corresponds to side of length 7 and side of length 16 corresponds to side of length q. This leads to the following proportion: $\frac{16}{7}=\frac{16}{q}$ Solving, $16\times7=16\times q$ $112=16q$ Dividing both sides by $16, $$q=7$.
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