Answer
$\theta = 60 ^{\circ}$
Work Step by Step
1.$x=1$ ; $y=1.73\approx \sqrt 3$
2.$r=\sqrt {(1)^{2}+(\sqrt 3)^{2}} = \sqrt 4 = 2$
3. $\sin\theta = \frac{y}{r}=\frac{\sqrt 3}{2}$
$\sin^{-1} \frac{\sqrt 3}{2}=60^{\circ}$
$\theta = 60^{\circ}$