Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises - Page 54: 83

Answer

$p=15$ $r= 15\sqrt 2$ $q=5\sqrt 6$ $t=10\sqrt 6$

Work Step by Step

The reference triangles provide ratios of the sides. As we start with the hypotenuse of a 30-60-90 triangle, we can determine its other tow sides. After, we use the ratios of a 45-45-90 triangle. $p=15$ $r = p\sqrt 2$ $r= 15\sqrt 2$ $q=\frac{r}{\sqrt 3}=\frac{15 \sqrt 2}{\sqrt 3}=5\sqrt 6$ $t=2q$ $t=10\sqrt 6$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.