Answer
$sin$ (-$\theta$) is negative in the interval (90$^{\circ}$,180$^{\circ}$).
Work Step by Step
$\sin$(-$\theta$)
$\theta$ is in the interval (90$^{\circ}$,180$^{\circ}$)
Therefore: $\theta$ exists in Quadrant II.
Therefore, -$\theta$ exists in Quadrant III.
All trigonometric functions are negative in Quadrant III, except for $\tan$ and $\cot$. Therefore $sin$ (-$\theta$) is negative in the interval (90$^{\circ}$,180$^{\circ}$).