Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises - Page 61: 82

Answer

$\theta=135^{\circ}$ or $225^{\circ}$

Work Step by Step

1. Since $sec\theta$ is negative, $\theta$ must be in quadrant II or III. 2. The absolute value of $sec\theta$ is $\sqrt 2$, therefore the reference angles is $45^{\circ}$. The actual angles in II and III quadrants are following: $180^{\circ}-45^{\circ}=135^{\circ}$ $180^{\circ}+45^{\circ}=225^{\circ}$
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