Answer
$f^{-1}(x) = \frac{x-3}{x-1}$
Work Step by Step
$f(x) = \frac{x-3}{x-1}$
Let $f(x) = y$
$y = \frac{x-3}{x-1}$
$x = \frac{y-3}{y-1}$
$xy - x = y-3$
$xy - y = x - 3$
$y(x -1) = x-3$
$y = \frac{x-3}{x-1}$
$f^{-1}(x) = \frac{x-3}{x-1}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Appendix A - Section A.2 - The Inverse of a Function - A.2 Problem Set - Page 496: 15
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