Answer
$\dfrac{2\pi}{|B|}$
Work Step by Step
As we are given that $y=A \sin (Bx) +D$
Thus, amplitude $=|A|$
and
the period is : $\dfrac{2\pi}{|B|}$
So, for the function $y= \sin (Bx) $
The period is : $\dfrac{2\pi}{|B|}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 4 - Section 4.2 - Amplitude, Reflection, and Period - 4.2 Problem Set - Page 203: 3
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