Answer
200,000 carbon atoms.
Work Step by Step
To determine the answer to this question we first need to know the volume of one page, which can be determined by the dimensions of one page. $(= 21.2 cm × 27.6 cm × 0.07 mm)$ gives us a page volume of $4 × 10^{–6} m^3$. This volume also happens to match the volume of a cube with a side length of 1.6 cm $(=3√4×10^{–6}m^2)$. Question 2-11 A gave us the $10^{23}$ atoms as the the amount of carbon atoms in the page. $3√10^{23}$ gives us 4.6 × 10^7, the amount of carbon atoms lined up on each side of the cube. If we take $(= 4.6 × 10^7 × 0.07 × 10^{–3} m/1.6 × 10^{–2} m)$ we get 200,00 carbon atoms for the page thickness.
