Answer
pH = 3.7
Work Step by Step
[H$^{+}$] of pure water: 10$^{-7}$ M
Increase in [H$^{+}$] due to HCl:
= ($50\times1$)/$250$ = $2\times10$$^{-4}$
= $-$log ($2\times10$$^{2}$) = $3.7$
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