Fundamentals of Biochemistry: Life at the Molecular Level 5th Edition

Published by Wiley
ISBN 10: 1118918401
ISBN 13: 978-1-11891-840-1

Chapter 4 - Amino Acids - Exercises - Page 95: 21

Answer

--->Tyrosine is an amino acid contains aromatic ring in its structure, ---> Aromatic rings are unsaturated hydrocarbons and its very well known that hydrocarbons are non polar in nature, ---> As we know that " Like dissolves like" and here, Aromatic ring of tyrosine increasing its non-polar character. Therefore Tyrosine amino acid are more soluble in less polar solvents such as Methanol, ethanol as compared to very highly polar water. ---> As in question its is given that tyrosine amino acid is barely soluble in water, because water is very polar solvent and tyrsoine amino acid is not highly polar in such extent. ---> Generally peptides are polar highly in nature. but as we will increase the number of tyrosine amino acids in peptide, area of non-polar part of peptide will increase (due to the increase of aromatic ring) and therefore the non-polar nature of peptide will increase. And this non-polar nature of peptide will make them more soluble in non-polar solvent and decrease its solubility in water (because water is polar in nature).

Work Step by Step

--->Tyrosine is an amino acid contains aromatic ring in its structure, ---> Aromatic rings are unsaturated hydrocarbons and its very well known that hydrocarbons are non polar in nature, ---> As we know that " Like dissolves like" and here, Aromatic ring of tyrosine increasing its non-polar character. Therefore Tyrosine amino acid are more soluble in less polar solvents such as Methanol, ethanol as compared to very highly polar water. ---> As in question its is given that tyrosine amino acid is barely soluble in water, because water is very polar solvent and tyrsoine amino acid is not highly polar in such extent. ---> Generally peptides are polar highly in nature. but as we will increase the number of tyrosine amino acids in peptide, area of non-polar part of peptide will increase (due to the increase of aromatic ring) and therefore the non-polar nature of peptide will increase. And this non-polar nature of peptide will make them more soluble in non-polar solvent and decrease its solubility in water (because water is polar in nature).
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.