Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 1 - The Foundations of Chemistry - Exercises - Measurements and Calculations - Page 39: 49

Answer

A)13,53 cm^{3} B)0.703 g/cm^{3}

Work Step by Step

A)The volume of the container is equal to the volume of the water, which the container is filled with. We shall calculate first the mass of the water: mass of the water=92,44g - 78,91g=13,53g Now let's divide the mass of the water by its density to get the volume of the container. V=13,51 g\div1,0000 g/cm^{3}=13,53cm^{3} B)The mass of the unknown liquid is equal to 88,42 g-78,91 g=9,51 g. The volume of the unknown liquid is equal to the volume of the container, which is 13,53 cm^{3}. Therefore the density of the liquid is: Density=9,51g\div13,53 cm^{3}= 0.703 g/cm^{3}
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