Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 12 - Gases and the Kinetic-Molecular Theory - Exercises - Charles's Law: The Volume-Temperature Relationship - Page 441: 29

Answer

124 L

Work Step by Step

$V_{1}=135\,L$ $T_{1}=(21+273)K= 294\,K$ $T_{2}= (-4+273)K=269\,K$ According to Charles's law, $\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$ (unchanging P and n) $\implies V_{2}=\frac{V_{1}T_{2}}{T_{1}}=\frac{135\,L\times269\,K}{294\,K}$ $=124\,L$
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