Answer
909. mL
Work Step by Step
$V_{1}$ = 256 mL
$P_{1}$ = 2.75 atm
$T_{1}$ = (16+273) K = 289 K
$P_{2}$ = 1.00 atm
$T_{2}$ = (100+273) K = 373 K
Using combined gas law,
$V_{2}$ = $\frac{P_{1}\times V_{1}\times T_{2}}{T_{1}\times P_{2}}$ = $\frac{2.75atm\times256 mL\times373K}{289K\times1.00atm}$ $\approx$ 909. mL
