Chemistry 10th Edition

by Whitten, Kenneth W.; Davis, Raymond E.; Peck, Larry; Stanley, George G.

Published by Brooks/Cole Publishing Co.

ISBN 10: 1133610668

ISBN 13: 978-1-13361-066-3

Chapter 15 - Chemical Thermodynamics - Exercises - Gibbs Free Energy Changes and Spontaneity - Page 606: 109

Answer

$-27.41\,kJ/mol$

Work Step by Step

We find: $\Delta G^{\circ}_{rxn}=\Sigma n_{p}\Delta G^{\circ}_{f}(products)-\Sigma n_{r}\Delta G^{\circ}_{f}(reactants)$ $=[\Delta G_{f}^{\circ}(Na^{+},aq)+\Delta G_{f}^{\circ}(I^{-},aq)]-[\Delta G_{f}^{\circ}(NaI,s)]$ $=[(-261.90\,kJ/mol)+(-51.57\,kJ/mol)]-(-286.06\,kJ/mol)$ $=-27.41\,kJ/mol$

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