Answer
$1127.51~g$
Work Step by Step
The given compound is $Cu_3(CO_3)_2(OH)$.
Find its molecular mass: $$M=3\cdot64+2\cdot12+7\cdot16+1\cdot1=329 ~\text{g/mole}$$
From the molecular mass, it can be concluded that $329~g$ of compound contains $192~g$ of copper.
To find the compound mass ($m$) that contains $658~g$ of copper use the following proportion:
$$\frac{329}{m}=\frac{192}{658}$$
By solving for $m$, it follows $m=1127.51~g$.
