Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 2 - Chemical Formulas and Composition Stoichiometrhy - Exercises - The Mole Concept - Page 75: 45

Answer

2.91 million

Work Step by Step

Calculate the number of moles of methane using Avogadro's number: $n=\dfrac{N}{N_A}$ $n=\dfrac{8.00\cdot 10^6}{6.022\cdot10^{23}}=1.33\cdot10^{-17}\ mol$ Calculate the molar mass of methane: Atomic weights: C - 12.011, H - 1.008 $M=12.011+4\cdot1.008=16.043\ g/mol$ Calculate the mass in this amount of methane: $n=\frac mM$ $m=1.33\cdot10^{-17}\ mol\cdot 16.043\ g/mol$ $m=2.13\cdot10^{-16}\ g$ This is the same as the mass of the propane sample. Calculate the molar mass of propane: $M=3\cdot 12.011+8\cdot 1.008=44.097\ g/mol$ Calculate the number of moles of propane: $n=\frac mM$ $n=\dfrac{2.13\cdot10^{-16}\ g}{44.097\ g/mol}=4.83\cdot10^{-18}\ mol$ Calculate the number of molecules of propane: $n=\frac N{N_A}$ $N=4.83\cdot10^{-18}\ mol\cdot 6.022\cdot 10^{23}=2.91\cdot 10^6\ molecules$ The sample has 2.91 million propane molecules.
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