Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 22 - Nuclear Chemistry - Exercises - Rates of Decay - Page 885: 54

Answer

75.9 min is needed to decay 92.5%. 135 min is needed to decay 99.0%.

Work Step by Step

Amount of radionuclide at the beginning $A_{0}=100$ When 92.5% is decayed, Amount of radionuclide remaining $A= 100.00-92.5=7.5$ Rate constant $k=\frac{0.693}{t_{1/2}}=\frac{0.693}{20.3\,min}=0.034138\,min^{-1}$ $\ln(\frac{A_{0}}{A})=kt$ $\implies \ln(\frac{100}{7.5})=2.59=0.034138\,min^{-1} \times t$ Or $t= \frac{2.59}{0.034138\,min^{-1} }=75.9 \,min$ When 99.0% is decayed, Amount of radionuclide remaining $A=100-99=1$ Then, $ \ln(\frac{100}{1})=4.605=0.034138\,min^{-1} \times t$ $\implies t= \frac{4.605}{0.034138\,min^{-1}}=135\,min$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.