Answer
a) methoxypropane
b) 2-methoxypropane
c) ethoxybenzene
d) methoxycyclohexane.
Work Step by Step
a) From the structure we can say that this is an ether (having $-O-$ group). For naming ether, we look for two sides of O atom individually. In this molecule, the left side of O has 1 C (meth) and right side has 3 C atoms (prop). The part having lower C is written first i.e. meth. then add 'oxy' for ether group. then the part having higher C is written i.e. prop. and lastly, 'ane' will be the ending name for alkane.
b) Look at two side of O atom. One side consists of 1 C and another side consists of 3 C. Here, we think $CH_{3}O-$ (methoxy) as a substituent. So, the right side has 3 C i.e. word root is 'prop'. Numbering the C atoms from 1 to 3. So, 'methoxy' group is present at C2 position i.e. '2-methoxy'. ending name will be 'ane'.
c) one $'O-CH_{2}CH_{3}'$ group i.e. ethoxy group is present as a substituent at benzene ring. So, the name will be 'ethoxybenzene'.
d) one $O-CH_{3}$ group i.e. methoxy is present as a substituent at cyclohexane ring. So, the name will be 'methoxycyclobutane.
