Answer
a) 3-methylbutanol
b) 2-methyl-1-cyclopentanol
c) 2-aminopropane
d) 2-chloropropene
e) p-dibromobenzene
f) N,N,N-triethylamine
g) phenoxy benzene / diphenyl ether
h) 2,4,6-tribromoaniline
Work Step by Step
a) Count the C in straight chain. It is 4. i.e. word root 'but'. functional group present here is $-OH$ in C1 Carbon (Numbering of C atom in straight chain is done so that the C associated with the functional group gets the minimum number) i.e. the ending name will be 'anol'. Now, one $CH_{3}$ group is present in C3 position as a substituent. So, '3-methyl' is added before word root. So, the complete name is 3-methylbutanol.
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b) This is a cyclic compound having 5 C ring. So, the word root is 'cyclopent'. Main functional group is OH i.e. ending name 'anol'. Now, numbering the ring C from 1 to 5 so that C associated with OH gets number 1. So, add '1' before word root to denote the position of OH group in the ring. Now, $CH_{3}$ group is present as a substituent at C2 position (numbering is done here anticlockwise so that the substituent gets the minimum number. If numbering is done clockwise the C associated with substituent will get no. 5 which is not acceptable) So, we add'2-methyl' before word root and the complete name is '2-methyl-1-cyclopentanol'.
c) Total no. of C in straight chain = 3. Word root 'prop'. Numbering them from 1 to 3. Now, $NH_{2}$ group is present as a substituent at C2 position. So, we add 2-amino before word root. ending name will be 'ane' for alkane. Complete name is 2-aminopropane.
d) Total no. of C in straight chain = 3. So, word root is 'prop'. Numbering them from 1 to 3 so that the main functional group '=' gets the minimum number. Hence it is done from right terminal side. So, the ending name is 'ene'. Now, a Cl atom is present as a substituent at C2 position. so, add '2-chloro before the word root. So, the complete name is '2-chloropropene'.
e) two 'Br' atoms are present at opposite direction (1,4 position) of the benzene ring. So, the name is 'p-dibromobenzene'.
f) three 'ethyl' groups are present on the N atom with three single bonds. Clearly, this is tertiary amine. So, the ending name is 'amine'. add 'triethyl' for three ethyl groups and add 'N,N,N' before 'triethyl' because three ethyl groups are attached with the N atom but not C atom.
g) Two phenyl group is present on both side of O atom. hence this is an ether and name will be diphenyl ether.
According to IUPAC, one Phenoxy ($-OC_{6}H_{5}$) group is present on the benzene ring. So, the name will be phenoxy benzene.
h) $C_{6}H_{5}-NH_{2}$ is aniline (common name). Now, three Br atoms are present at 2,4 and 6 position of aniline. So, the name is 2,4,6-tribromoaniline.
