Answer
$3CoCl_2+2K_3PO_4\rightarrow Co_3(PO_4)_2+6KCl$
Work Step by Step
The following reaction takes place:
$3CoCl_2+2K_3PO_4\rightarrow Co_3(PO_4)_2+6KCl$
$Co_3(PO_4)_2$ is a suspended purple solid.
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