Chemistry 10th Edition

by Whitten, Kenneth W.; Davis, Raymond E.; Peck, Larry; Stanley, George G.

Published by Brooks/Cole Publishing Co.

ISBN 10: 1133610668

ISBN 13: 978-1-13361-066-3

Chapter 4 - The Structure of Atoms - Exercises - The Wave-Particle View of Matter - Page 168: 77

Answer

Wavelength, λ= 1.68$\times10^{-10}$ m

Work Step by Step

Using de Broglie's relation, we get λ= $\frac{6.626\times10^{-34}Js}{1.67\times10^{-27}kg\times2360 ms^{-1}}$ =1.68$\times10^{-10}$ m

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