Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 1 - Chemistry: The Study of Change - Questions & Problems - Page 31: 1.38

Answer

a) 1.28 km b) 3.18$\times$$10^{-3}$mg c) 8.14$\times$$10^{7}$dm e) 3.8 m/s

Work Step by Step

a) 7.310 km$\div$5.70 km Simply divide 7.310 km$\div$5.70 km = 1.28245614 km since the 5.70 has the lower number of significant figures that is 3 sig figs the answer should be reported to 3 significant figures the answer will be 1.28 km b) (3.26$\times$$10^{-3}$mg)-(7.88$\times$$10^{-5}$mg) In doing subtraction or addition of scientific notation the exponents must have the same numbers thus, 3.26$\times$$10^{-3}$ = 3.26$\times$$10^{-3}$ 7.88$\times$$10^{-5}$ = 0.0788$\times$$10^{-3}$ (3.26$\times$$10^{-3}$ mg)-(0.0788$\times$$10^{-3}$ mg)=3.1812$\times$$10^{-3}$ mg since the both terms has 3 sig figs, the answer must be reported to 3 sig figs that is 3.18$\times$$10^{-3}$ mg c) (4.02$\times$$10^{6}$ dm)+(7.74$\times$$10^{7}$ dm) Again the same procedure from number letter b applies to letter c 4.02$\times$$10^{6}$ = 0.0402$\times$$10^{7}$ 7.74$\times$$10^{7}$ = 7.74$\times$$10^{7}$ (0.0402$\times$$10^{7}$ dm)+(7.74$\times$$10^{7}$ dm)=8.14$\times$$10^{7}$dm If you get this answer, 81420000 simply convert it to scientific notation and report to 3 sig figs d) $\frac{(7.8m-0.34m)}{(1.15s+0.82s)}$ In doing chain calculations, simplify first the numerator and the denominator and report them to the correct sig figs (7.8m-0.34m)=7.5m (1.15s+0.82s)=2.0s $\frac{(7.5m)}{(2.0s)}$=3.75 m/s since both terms have 2 sig figs the answer must be reported to 2 sig figs thus, the answer is 3.8 m/s
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