Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 1 - Chemistry: The Study of Change - Questions & Problems - Page 31: 1.39

Answer

a) $226dm$ b) $2.54\times10^{-5}$ c) $5.56\times10^{-1}L$ d) $1.06\times10^{-2}g/cm^3$

Work Step by Step

a) $22.6m=22.6\times10^1dm=226dm$ b) $25.4mg=25.4\times10^{-6}kg=2.54\times10^{-5}$ c) $556mL=556\times10^{-3}L=5.56\times10^{-1}L$ d) $\frac{10.6kg}{1m^3}=\frac{10600g}{10^6cm^3}$ $=1.06\times10^{-2}g/cm^3$
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