Answer
Please see the work below.
Work Step by Step
We know that
$(5.11\times 10^3Kg\space ore)\times \frac{34.63\%Cu}{100\%\space ore}\times \frac{1000g}{1Kg}=1.77\times 10^6gCu$
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 1 - Chemistry: The Study of Change - Questions & Problems - Page 33: 1.81
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