Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 1 - Chemistry: The Study of Change - Questions & Problems - Page 33: 1.85

Answer

$7.3 \times 10^{21} kg$

Work Step by Step

First, we need to calculate the mass of Earth's crust: Mass of crust = $ 5.9\times10^{21} tons\times\frac{0.50\% crust}{100 \% Earth} =2.95 \times 10^{19} tons $ The mass of silicon in the crust is then: Mass of silicon = $ 2.95 \times 10^{19} tons \times\frac{27.2\% Si}{100\% crust} \times \frac{2000 lb}{1 ton} \times\frac{453.6 g}{1 lb} \times\frac{1 kg}{1000 g} = 7.3 \times 10^{21} kg$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.