Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 19 - Nuclear Chemistry - Questions & Problems - Page 892: 19.20

Answer

$0.556 * 10 ^{10}kgs^{-1}$.

Work Step by Step

From Einstein's equation, $E = mc^{2}$, so, $m = \frac{E}{c^{2}}$ $m = \frac{5 * 10^{26}Js^{-1}}{(3*10^{8}ms^{-1})^{2}} = 0.556 * 10 ^{10}kgs^{-1}$ Hence, the mass loss of sun is $0.556 * 10 ^{10}kgs^{-1}$.
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