Chemistry 12th Edition

by Chang, Raymond; Goldsby, Kenneth

Published by McGraw-Hill Education

ISBN 10: 0078021510

ISBN 13: 978-0-07802-151-0

Chapter 20 - Chemistry in the Atmosphere - Questions & Problems - Page 925: 20.6

Answer

$ 3.3*10^{-4}atm$

Work Step by Step

We find: $P_{CO_{2}} = X_{CO_{2}}P_{T} = 3.3 * 10^{-4} (754mmHg)*\frac{1 atm}{760mmHg} = 3.3*10^{-4}atm$

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