Answer
460$^{\circ}$C; 850$^{\circ}$F
Work Step by Step
T ($^{\circ}$C)=T(in K)-273.15
$=(7.3\times 10^{2}-273.15)^{\circ}C=460^{\circ}C$
($456.85^{\circ}C$ is rounded off to two significant figures).
Now, the temperature in Celcius can be converted to Fahrenheit using the formula
$F=\frac{9}{5}C+32=(\frac{9}{5}\times456.85+32)^{\circ}F$
$=850^{\circ}F$
