Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 1 - Questions and Problems - Page 35: 1.110

Answer

$1.3\times 10^3 mL\space soln$

Work Step by Step

The volume of chlorine solution in $mL$ can be determined as follows: First of all, we convert the gallons of water into milliliters $Water \space volume=2\times 10^4 gal\times 3.79L \times 1000=7580\times 10^4mL$ Now the mass of chlorine is given as $mass \space of \space chlorine=7580\times 10^4mL\times \frac{1g\space H_2O}{1mL\space H_2O} \times\frac{1g \space Cl_2}{10^6\space g H_2O}=7580\times 10^{-2}g $ Given that the solution contains 6 percent chlorine by mass $\implies Volume \space of \space chlorine \space solution=7580\times 10^{-2}g \times \frac{100 g \space soln}{6g}\times \frac{1mL\space soln}{1g\space soln}=1.3\times 10^3 mL\space soln$
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