Answer
The complete balanced equation for that reaction is:
$HCl(aq) + NaHCO_3(s) \longrightarrow CO_2(g) + H_2O(l) + NaCl(aq)$
Work Step by Step
1. Identify the type of Acid-Base reaction:
Since $NaHCO_3$ has the $HCO_3^-$ ion, and it is reacting with an acid (HCl), this is a reaction between an acid and a bicarbonate.
$Acid + Bicarbonate \longrightarrow CO_2(g) + H_2O(l) + Salt$
2. Find the identity of the salt.
The $HCl$ will donate a $H^+$ (since it is an acid). "$Cl^-$" will remain.
The bicarbonate ion ($HCO_3^-)$ will react, leaving the sodium ion ($Na^+$) alone.
Therefore, the produced salt is: $NaCl$.
3. Follow the pattern:
$HCl(aq) + NaHCO_3(s) \longrightarrow CO_2(g) + H_2O(l) + NaCl(aq)$
