Answer
\[\underline{1.99\times {{10}^{5}}\text{ kg}}\]
Work Step by Step
\[1\text{ }f{{t}^{3}}=28,316.8\text{ c}{{\text{m}}^{3}}\]
Thus, volume of the iceberg in cubic centimeters will be written as follows:
\[\begin{align}
& V=\left( 7655\times 28,316.8 \right)\text{ c}{{\text{m}}^{3}} \\
& =216,765,104\text{ c}{{\text{m}}^{3}}
\end{align}\]
Density of ice is \[0.92\text{ g/c}{{\text{m}}^{\text{3}}}\]. The relation between density\[\left( d \right)\] and mass\[\left( m \right)\] is as follows:
\[m=\left( V \right)\left( d \right)\]
Here, V is volume.
Thus, mass of ice is written as follows:
\[\begin{align}
& m=\left( V \right)\left( d \right) \\
& =\left( 216,765,104\text{ c}{{\text{m}}^{3}} \right)\left( 0.92\text{ g/c}{{\text{m}}^{3}} \right) \\
& =199,423,896\text{ g}
\end{align}\]
Now, convert this mass of ice from grams to kilograms by the use of the following relation:
\[1\text{ kg}=1000\text{ g}\]
Thus, mass of ice in kilogram is written as follows:
\[\begin{align}
& m=199,423,896\times {{10}^{-3}}\text{ kg} \\
& =\text{1}\text{.99}\times {{10}^{5}}\text{ kg}
\end{align}\]
The mass of ice in kilograms is \[\underline{1.99\times {{10}^{5}}\text{ kg}}\].
