Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 2 - Atoms, Molecules, and Ions - Exercises - Page 75: 2.20c

Answer

$V=1.0*10^{-29}m^3$

Work Step by Step

The formula for volume of a sphere is as follows: $V=\frac{4}{3}πr^3$ The radius is half the diameter, which is $2.7*10^{-8} cm$ or $2.7*10^{-8} cm*\frac{1m}{100cm}=2.7*10^{-10} m$ You convert your answer into meters because the question asks for the volume in $m^{3}$. The radius is then just $\frac{2.7*10^{-10} m}{2}=1.35*10^{-10}m$ Then use this value for $r$ in $V=\frac{4}{3}πr^3$. This gets you a $V=1.0306*10^{-29}m^3$. Rounding to the proper number of significant figures gets you $V=1.0*10^{-29}m^3$ your final answer
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