Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 115: 3.52b

Answer

$C_4H_8O_2$

Work Step by Step

Given: $C_2H_4O$, $88$g/mol. Find mass of $C_2H_4O$ $= 44.052$ g/mol Divide given molar mass. 88(g/mol)/44(g/mol) = 2 Multiply compound by 2 to get molecular formula $C_4H_8O_2$
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