Answer
2.25 Moles of $N_{2}$ are produced
Work Step by Step
For every 2 moles of $NaN_{3}$ used there are 3 moles of $N_{2}$ produced
1.5 moles of $NaN_{3}$ $\times$ ( $\frac{3 moles N_{2}}{2 moles NaN_{3}}$) = 2.25 moles of $N_{2}$
Chemistry: The Central Science (13th Edition)
by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.
Published by
Prentice Hall
ISBN 10:
0321910419
ISBN 13:
978-0-32191-041-7
Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 117: 3.67a
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