Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 117: 3.68b

Answer

Approximately 35.0877 grams.

Work Step by Step

The proportion is: 25 mols $O_2$ for 2 mol $C_8H_{18}$. 25 mols $O_2$ in grams: 25*(16*2) = 800g. 2 mol $C_8H_{18}$ in grams: 2*(8*12+18*1) = 228g. 800g of $O_2$ for 228g of $C_8H_{18}$: $\frac{800}{x} = \frac{228}{10}$ 228x = 800*10 228x = 8000 x = $\frac{8000}{228}$ x $\approx$ 35.0877
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