Answer
a. There are 24 moles of H in 1.0 mole of quinine.
b. There are $1.0\times 10^2$ moles of C in 5.0 moles of quinine.
c. There is a total of 0.040 mole of N in 0.020 mole of quinine.
Work Step by Step
a. Each $ C_{20}H_{24}N_2O_2 $ has 24 H atoms, thus:$$ 1.0 \space mole \space C_{20}H_{24}N_2O_2 \times \frac{ 24 \space moles \ H }{1 \space mole \space C_{20}H_{24}N_2O_2 } = 24 \space moles \space H $$
b. Each $ C_{20}H_{24}N_2O_2 $ has 20 C atoms, thus:$$ 5.0 \space moles \space C_{20}H_{24}N_2O_2 \times \frac{ 20 \space moles \ C }{1 \space mole \space C_{20}H_{24}N_2O_2 } = 1.0 \times 10^2 \space moles \space C $$
c. Each $ C_{20}H_{24}N_2O_2 $ has 2 N atoms, thus:$$ 0.020 \space mole \space C_{20}H_{24}N_2O_2 \times \frac{ 2 \space moles \ N }{1 \space mole \space C_{20}H_{24}N_2O_2 } = 0.040 \space mole \space N $$
