Answer
a. There are 32.2 moles of C in 2,30 moles of naproxen.
b. There are 6.22 moles of H in 0.444 mole of naproxen.
c. There is a total of 0.230 mole of O in 0.0765 mole of naproxen.
Work Step by Step
a. Each $ C_{14}H_{14}O_3 $ has 14 C atoms, thus:$$ 2.30 \space moles \space C_{14}H_{14}O_3 \times \frac{ 14 \space moles \ C }{1 \space mole \space C_{14}H_{14}O_3 } = 32.2 \space moles \space C $$
b. Each $ C_{14}H_{14}O_3 $ has 14 H atoms, thus:$$ 0.444 \space mole \space C_{14}H_{14}O_3 \times \frac{ 14 \space moles \ H }{1 \space mole \space C_{14}H_{14}O_3 } = 6.22 \space moles \space H $$
c. Each $ C_{14}H_{14}O_3 $ has 3 O atoms, thus:$$ 0.0765 \space mole \space C_{14}H_{14}O_3 \times \frac{ 3 \space moles \ O }{1 \space mole \space C_{14}H_{14}O_3 } = 0.230 \space mole \space O $$
