Answer
The equation for the acid base reaction and the conjuagate acids and bases are shown in the picture. The equilibrium favors the products.
Work Step by Step
$OH^-$ in $NaOH$ can accept a proton from $H_2S$. So the following reaction will take place. $Na^+$ $HS^-$ is the conjugate base because it losses a proton and $H_2O$$ is conjugate acid because it gains a proton. Stronger acid and base are on the reactant side. The equilibrium will favor the weaker side and thus, products will be favored.
None of them are resonance stabilized. The conjugate base has larger anion size.
