Answer
The lewis structure is shown in the picture.
Work Step by Step
1) Draw the structure in the sequence shown in the formula.
2) Count the number of valence electrons involved in the bonding, which is 24. There should be 1+1+1+6+6+6+6+6+4+1+1+1 = 40e. Make a one more bond between the S and O bonds that are not connected to $CH_3$. now there are 28 e.
3) Since O,C, H, S have already made the max bonds possible, place the remaining electrons as lone pairs, two on each O.
4) Now count the valence electrons, it should be 40e.
