Answer
Molecular formula: $C_6H_{12}O_2$
Work Step by Step
The empirical weight of $C_3H_6O$ = 58
The molecular weight = 117
To find the number to multiply the empirical formula: 117/58 = 2
($C_3H_6O$) x 2 = $C_6H_{12}O_2$
Organic Chemistry (8th Edition)
by Wade Jr., L. G.
Published by
Pearson
ISBN 10:
0321768418
ISBN 13:
978-0-32176-841-4
Chapter 1 - Introduction and Review - Study Problems - Page 37: 1-33 b
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