Physical Chemistry: Thermodynamics, Structure, and Change

Published by W. H. Freeman
ISBN 10: 1429290196
ISBN 13: 978-1-42929-019-7

Chapter 1 - Topic 1A - The perfect gas - Exercises - Page 55: 1A.13(a)

Answer

The mole fractions of Nitrogen and Hydrogen gas are 0.333 and 0.667 respectively.

Work Step by Step

Given information in the question, Number of moles of $\mathrm{H}_{2}=2$ moles Number of moles of $\mathrm{N}_{2}=1$ mole Volume of the vessel $=22.4 \mathrm{dm}^{3}=22.4$ litres Temperature $=\mathrm{T}=273.15 \mathrm{K}$ $\begin{aligned} \text { Total number of moles in the system } &=\text { Moles of Nitrogen }+\text { Moles of Hydrogen } \\ &=1+2 \text { moles } \\ &=3 \text { moles } \end{aligned}$ Calculating the Mole fraction Mole fraction of an element in a combined system is defined as: Mole fraction of an element $=\frac{\text { Number of moles of the element }}{\text { Total number of moles in the system }}$ (1) Substituting the values and calculating mole fraction of Nitrogen and Hydrogen, $$ \begin{aligned} \text { Mole fraction of Nitrogen } &=\frac{\text { Number of moles of Nitrogen }}{\text { Total number of moles in the system }} \\ &=\frac{1}{3} \\ &=0.333 \end{aligned} $$ $\begin{aligned} \text { Mole fraction of Hydrogen } &=\frac{\text { Number of moles of Hydrogen }}{\text { Total number of moles in the system }} \\ &=\frac{2}{3} \\ &=0.667 \end{aligned}$ Hence the mole fractions of Nitrogen and Hydrogen gas are 0.333 and 0.667 respectively.
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