College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Problems - Page 23: 85

Answer

a) $2.4\times10^{5}km/h$ b) $10min$

Work Step by Step

a) Speed in km per hour = $(120 paces/1 min) \times (7 leagues/1 pace ) \times ( 4.8 km/1 league )\times (60 min/ 1hr)=2.4\times10^{5}km/hr$ b) The circumference of the earth is approximately 40000km. The time taken to march around the earth is found by dividing the distance by the speed. Time of travel = $40000\times (1hr/2.4\times10^{5}km)\times (60min/1 hr) = 10min$
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