College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Problems - Page 23: 86

Answer

a) $2890in^{3}$ b) $0.495$ cubic cubits

Work Step by Step

a) $\frac{12.5 US gal}{1}\times\frac{3.785L}{US gal}\times\frac{0.06102in^{3}}{mL}=2890in^{3}$ b) $\frac{2887in^{3}}{1}\times(\frac{1 cubit}{18in})^{3}=0.495$ cubic cubits
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