College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 2 - Problems - Page 66: 38

Answer

(a) The magnitude of the net force is 30 N directed to the right. (b) The magnitude of the net force is zero. (c) The magnitude of the net force is 18 N directed downward.

Work Step by Step

(a) We can find the magnitude of the net force $F$: $F = 40~N - 10~N = 30~N$ (directed to the right) The magnitude of the net force is 30 N directed to the right. (b) We can find the magnitude of each component of the net force $F$: $F_x = 10~N - 10~N = 0$ $F_y = 18~N - 18~N = 0$ The magnitude of the net force is zero. (c) We can find the magnitude of each component of the net force $F$: $F_x = 10~N - 10~N = 0$ $F_y = 18~N$ directed downward The magnitude of the net force is 18 N directed downward.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.