College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 1 - Measurement and Problem Solving - Learning Path Questions and Exercises - Exercises - Page 30: 40

Answer

a). 137.16m by 22.86m by 13.716m b). $4.3\times 10^{3} m^{3}$

Work Step by Step

1 cubit = 0.5 yard But, 1 yard = 0.9144 m. So, $ 1 cubit = 0.5 \times 0.9144 m = 0.4572 m.$ a). $300 cubits=300 \times 0.4572 m = 137.16m$ $50 cubits=50 \times .4572 m = 22.86m$ $30 cubits=30 \times 0.4572 m = 13.716m$ So the dimension of the ark is 137.16m by 22.86m by 13.716m b). Volume = $137.16\times 22.86 \times 13.716 m^{3}$ $=4.3\times 10^{3} m^{3}$
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