Chapter 1 - Measurement and Problem Solving - Learning Path Questions and Exercises - Exercises - Page 30: 48

$32.3 ft^{3}$ approximately.

We have 1 ft = 30.48 cm. Now, H=130 cm, W=105 cm, D= 67 cm. So, $V=H\times W\times D= 130cm \times 105cm \times 67cm$ $=\frac{130}{30.48} \times \frac{105}{30.48} \times \frac{67}{30.48} ft^{3}$ $\approx 32.3 ft^{3}$