College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 96: 1

Answer

(a) $208.33\,\mathrm{km/h}$ (b) $54.16\,\mathrm{km/h}$

Work Step by Step

(a) The horizontal component is given by $v_x=v\cos15^{\circ}$. For $v_x=200$, we have $v=200/0.96=208.33\,\mathrm{km/h}$. (b) The vertical component is given by $v_y=v\sin15^{\circ}$. For $v_x=208.33$, we have $v=208.33\times 0.26=54.16\,\mathrm{km/h}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.