Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 96: 7

$a). 70m$ $b). 0.57min, 0.43min$

a). Base of the triangle = $50 \times cos37^{\circ}=50\times 0.8=40m$ Thus, the other side = $\sqrt (50^{2}+40^{2})=30m$ So, total distance =$40+30=70m$ b). The student walked around the route for 1 min, she spent on 40m side for $=\frac{40}{70}\times1=0.57min$ she spent on 30m side for $=\frac{30}{70}\times1=0.43min$