College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 97: 8

Answer

$(1.75m, -1.75m)$

Work Step by Step

$distance=1.50\times1.65=2.475m$ The ball is in fourth quadrant x coordinate= $+ 2.475 cos(45^{\circ})=1.75m$ y coordinate= $- 2.475 cos(45^{\circ})=-1.75m$ So, the coordinates are $(1.75m, -1.75m)$
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